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Question:
If \( x^2+5x-14=0\). What are the values of x − 1?
A
−8, 1.
explanation
First, solve \( x^2+5x-14=0\) by factoring.
\( x^2+5x-14=0\)
(x + 7)(x – 2) = 0
x + 7 = 0 or x − 2 = 0
x = −7 or x = 2
Next, substitute both values, one at a time, into the expression x – 1 to obtain
–7 – 1 = –8 and 2 – 1 = 1. Therefore, the correct choice is –8, 1.
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