If \( x^2+5x-14=0\). What are the values of \(x − 1\)?

First, solve \( x^2+5x-14=0\) by factoring.
\( x^2+5x-14=0\)
\((x + 7)(x – 2) = 0\)
\(x + 7 = 0\) or \(x − 2 = 0\)
\(x = −7\) or \(x = 2\)
Next, substitute both values, one at a time, into the expression \(x – 1\) to obtain
\(–7 – 1 = –8\) and \(2 – 1 = 1\).
Therefore, the correct choice is\( –8, 1\).