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If \( x^2+5x-14=0\). What are the values of x − 1?

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Question:

A
−8, 1.

explanation

First, solve \( x^2+5x-14=0\) by factoring.

\( x^2+5x-14=0\)

(x + 7)(x – 2) = 0

x + 7 = 0 or x − 2 = 0

x = −7 or x = 2

Next, substitute both values, one at a time, into the expression x – 1 to obtain

–7 – 1 = –8 and 2 – 1 = 1. Therefore, the correct choice is –8, 1.

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