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If \( x^2+5x-14=0\). What are the values of \(x − 1\)?

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Question:

A
\(−8, 1\)

explanation

First, solve \( x^2+5x-14=0\) by factoring.

\( x^2+5x-14=0\)

\((x + 7)(x – 2) = 0\)

\(x + 7 = 0\) or \(x − 2 = 0\)

\(x = −7\) or \(x = 2\)

Next, substitute both values, one at a time, into the expression \(x – 1\) to obtain

\(–7 – 1 = –8\) and \(2 – 1 = 1\).

Therefore, the correct choice is\( –8, 1\).

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