What is the value of \(\frac{{ (x^2+x+3) } }{{(x+2)}}\) when \(x = -1\)?

A \(3\)

explanation

\(\frac{{ (x^2+x+3) } }{{(x+2)}} =((-1)^2+(-1)+3) \div ((-1)+2)\) when \(x=-1\)
\(\frac{{(1-1+3)} }{{(-1+2)}} = \frac{{3} }{{1}}=3 \)

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