A rectangle’s length is 3 feet longer than twice its width. The area of the rectangle is 44\(feet^2\) . The rectangle’s length is how many feet?

Let W = the rectangle’s width. Then 2W + 3 = the rectangle’s length. Using the formula for the area of a rectangle (and omitting the units), solve the following equation for W and then determine 2W + 3, the rectangle’s length:
LW = A
(2W + 3) W = 44
\(2W^2+3W-44=0 \)
(2W +11)(W – 4) = 0
2W + 11 = 0 or W - 4 = 0
W = −5.5 (reject) or W = 4
2W + 3 = 8+ 3 = 11