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Question:

# A rectangle’s length is 3 feet longer than twice its width. The area of the rectangle is 44$feet^2$ . The rectangle’s length is how many feet?

A 11
explanation

Let W = the rectangle’s width. Then 2W + 3 = the rectangle’s length. Using the formula for the area of a rectangle (and omitting the units), solve the following equation for W and then determine 2W + 3, the rectangle’s length:
LW = A
(2W + 3) W = 44
$2W^2+3W-44=0$
(2W +11)(W – 4) = 0
2W + 11 = 0 or W - 4 = 0
W = −5.5 (reject) or W = 4
2W + 3 = 8+ 3 = 11