A rectangle’s length is 3 feet longer than twice its width. The area of the rectangle is \(44\text{ }feet^2\). The rectangle’s length is how many feet?

Let W = the rectangle’s width. Then 2W + 3 = the rectangle’s length. Using the formula for the area of a rectangle (and omitting the units), solve the following equation for W and then determine 2W + 3, the rectangle’s length:
\(LW = A\)
\((2W + 3) W = 44\)
\(2W^2+3W-44=0 \)
\( (2W +11)(W – 4) = 0\)
\(2W + 11 = 0\) or \(W - 4 = 0 \)
\(W = −5.5\) (reject) or \(W = 4\)
\(2W + 3 = 8+ 3 = 11\)